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1. In each case, find the derivative dy/dx

a) [itex]y = 6 - 7x[/itex]

b) [itex]y = {x + 1}/{x - 1}[/itex]

c) [itex]y = 3x^2[/itex]

The book didn't go into too much detail on the dy/dx thing, and so I don't really have any idea on what to do.

2. Find an equation of the straight line that is tangent to the graph of [itex]f(x) = \sqrt{x + 1}[/itex] and parallel to [itex]x - 6y + 4 = 0[/itex].

I figured that I could at least find the slope of the line, since it's parallel to [itex]x - 6y + 4 = 0[/itex]. I calculated the slope from this to be 1/6, and since the lines are parallel, then the slope of the tangent to the graph of f(x) = \sqrt{x + 1}[/itex] must also be 1/6. I didn't really know what to do after this.

3. For each function, use the definition of the derivative to dtermine dy/dx, where a, b, c, and m are constants.

a) [itex]y = c[/itex]

b) [itex]y = x[/itex]

c) [itex]y = mx + b[/itex]

c) [itex]y = ax^2 + bx + c[/itex]

I was thinking that I might have to substitute the y in each case for the y in dy/dx, but I'm not really sure, as I said earlier, the book didn't go into dy/dx all that much.