- #1

leright

- 1,316

- 19

Also, if he wants us to find the capacitance by finding the voltage between the two spheres, I can just determine the e-field due to one of the spheres, and then determine the voltage by integrating e-field with respect to r between the distance of the two spheres, right? I am just having lots of trouble thinking through the details if these types of problems, and want to know if my logic is right...these concepts are not 100% clear to me yet..

Also, I'm 90% sure he is going to give us a quadrupole problem, where we have 4 point charges on an axis, each charge a distance 'd' apart. The charge config is a + - + - system, where the charge magnitudes are identical, but just different signs. We need to find the e-field on a point a distance 'a' from the first charge where a >> d, and this point is on the same axis as the 4 charges...I would reason that the e-field due to the individual charges cancel out, since a ~= a + d ~= a + 2d ~= a + 3d, leaving a net e-field at thta point of zero...but this line of reasoning is not good enough for my prof...be wants us to use the binomial theorem. I didn't follow his lecture on this example, and nobody else in the class seemed to either. I asked him about it, but he was still not much help. :( I was hoping you guys have seen this problem betore and you could point me in the right direction.

Also, we haven't discussed magnetic fields yet, but I am aware that e-fields are different from mag-fields. I have the vague understanding that mag-fields are caused by charge current, whereas e-fields are caused by stationary charges that cause potentials on various regions in space...but, my intuitive understanding of magnetism is the same thing...they both cause potentials, but are magnetic fields not due to charges, where e-fields are? If mag-fields are not due to charges, then what are they caused by? So many questions unanswered and it makes my head spin...I am absolutely losts with most of this stuff...it is driving me crazy.

Any help would be greatly appreciated. I will likely add more questions later.