# Some limit proofs

1. Jun 26, 2004

### Ed Quanta

How do I show |Rez - Rez0|<E whenever 0<|z-z0|<D is true, where E and D are real number greater than 0, and z is obviously a complex number?

In other words, proving that the lim of Rez (as z approaches z0)=Rez0.

2. Jun 26, 2004

### matt grime

As literally written, your first statement is not true and doesn't imply the second one; it depends on what E and D are.

However, since |Rez - Rez0| <= |z-z0| is all you need to know you should be able to work it out.

Last edited: Jun 26, 2004
3. Jun 27, 2004

### HallsofIvy

Staff Emeritus
What you mean is to show that, given any E>0, there exist a D>0 such that |Re(z)- Re(z0)|<E whenever |z-z0|< D. Matt grime's point is that that is very different from saying that |Re(z)- Re(z0)|< E whenever |z-z0|< D for any E and D.

And, as he said, it follows from the fact that |Re(z)-Re(z0)|< |z- z0|.