Some simple algebra that's bugging me

  • Thread starter airkapp
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    Algebra
In summary, algebra is a branch of mathematics that uses symbols to solve equations and understand numerical relationships. It is important because it has real-world applications and provides the foundation for more advanced math concepts. Basic operations in algebra include addition, subtraction, multiplication, and division. To solve for a variable in an equation, you need to isolate the variable using inverse operations. The properties of algebra include the commutative, associative, and distributive properties, which allow us to manipulate expressions.
  • #1
airkapp
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550,000Hz = 1 / (2 π √ L*1800E-12C )

I'm trying to isolate for L but I can't seem to do it right.

multiply 550,000 * (2 π √ L*1800E-12 )

then divide 1 by 550,000 and put 4π over it. then square both sides to get ride of the sq. root giving something like..

L = (4π^2 * 1.8E-9C) / 550,000Hz
 
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  • #2
[tex]550,000=\frac{1}{2\pi\sqrt{L*1.8*10^{-9}}}[/tex]
[tex]\sqrt{L*1.8*10^{-9}}=\frac{1}{2\pi*550,000}[/tex]
[tex]L*1.8*10^{-9}=(\frac{1}{2\pi*550,000})^2[/tex]
[tex]L=\frac{(\frac{1}{2\pi*550,000})^2}{1.8*10^{-9}}[/tex]
 
  • #3
^2

First of all, great job on attempting to solve this algebra problem! It can definitely be frustrating trying to isolate for a variable in a complex equation. Let's break down the steps you took:

1. Multiply 550,000 by (2 π √ L*1800E-12): This step is correct, as you are essentially bringing the L variable to one side of the equation by multiplying it with the other terms.

2. Divide 1 by 550,000 and put 4π over it: This step is also correct, as you are essentially dividing both sides of the equation by 550,000 to isolate L.

3. Square both sides: This step is where the mistake occurs. When you square both sides, you must square every term on both sides of the equation, not just the left side. This means that the right side should also be squared, giving you the equation:

(550,000Hz)^2 = (4π^2 * 1.8E-9C) / L

4. Solve for L: To isolate L, you can multiply both sides by L, then divide by (550,000Hz)^2. This will give you the final equation:

L = (4π^2 * 1.8E-9C) / (550,000Hz)^2

I hope this helps clarify the steps you took and how to correctly isolate for L in this equation. Keep practicing and you'll become a pro at solving algebra problems in no time!
 

1. What is algebra?

Algebra is a branch of mathematics that deals with symbols and the rules for manipulating these symbols to solve equations and analyze mathematical relationships.

2. Why is algebra important?

Algebra is important because it helps us solve real-world problems and make sense of numerical relationships. It also lays the foundation for more advanced mathematical concepts.

3. What are some basic algebraic operations?

Some basic algebraic operations include addition, subtraction, multiplication, and division. These operations can be performed on numbers, variables, or a combination of both.

4. How do I solve for a variable in an equation?

To solve for a variable in an equation, you need to isolate the variable on one side of the equation by using inverse operations. This means performing the opposite operation on both sides of the equation until the variable is alone on one side.

5. What are the properties of algebra?

The properties of algebra include the commutative, associative, and distributive properties. The commutative property states that the order of numbers in addition and multiplication does not change the result. The associative property states that the grouping of numbers in addition and multiplication does not change the result. The distributive property allows us to expand expressions like a(b+c) to ab+ac.

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