 #1
ReubenDS
 3
 1
 TL;DR Summary

Summation of Summation method
Extracting value for n of a Summation
1. I have come across a few times I would like a more straightforward way to run a summation function on a summation function. I don't have the educational groundwork to know if there is another way to do this or a good technique to simplify these problems.
example:
2*Sum[2x1*Sum[Divide[2x1,2],{x,1,n}],{x,1,n}]
Where 2* summation of all whole integers of the function (2x1)*summation of all whole integers of the function (2x1)/2 where x=1 to n for both summations.
2. It has struck me from time to time that I would like to reverse a summation function to derive an unknown limit for a known resultant of the summation.
example:
(Sum[2x1,{x,1,n}])=2704
Where the summation of all whole integers of the function 2x1 for x=1 to n, equals 2704 what is the value of n?
example:
2*Sum[2x1*Sum[Divide[2x1,2],{x,1,n}],{x,1,n}]
Where 2* summation of all whole integers of the function (2x1)*summation of all whole integers of the function (2x1)/2 where x=1 to n for both summations.
2. It has struck me from time to time that I would like to reverse a summation function to derive an unknown limit for a known resultant of the summation.
example:
(Sum[2x1,{x,1,n}])=2704
Where the summation of all whole integers of the function 2x1 for x=1 to n, equals 2704 what is the value of n?