(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

1. Two forces of equal magnitude are acting on a particle along two different directions. Let [tex]\theta[/tex]

be the angle between them. If direction of one vector is reversed , the magnitude of resultant is halved. Find tan[tex]\theta[/tex].

2.The resultant of the two vectors having magnitudes 5 and 4 is 1. what is the magnitude of their cross product?

2. Relevant equations

3. The attempt at a solution

for 1st one-

tan[tex]\theta[/tex] = Acos[tex]\theta[/tex][tex]\frac{}{}[/tex]A + Asin[tex]\theta[/tex]

and tan2[tex]\theta[/tex] = 2Acos[tex]\theta[/tex][tex]\frac{}{}[/tex]A + Asin[tex]\theta[/tex]

2nd one -

i get cos[tex]\theta[/tex] as -1.

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# Homework Help: Some vector problems.

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