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Due to earth's rotation, a plumb bob may not hang exactly along the direction of the Earth's gravitational force on the plumb bob but may deviate slightly from that direction. (a) show that the deflection [tex]\theta[/tex]is given by [tex]\theta = (\frac{2\pi^2R}{gT^2})sin(2L)[/tex], where R is the radius of the Earth and T is the period of the Earth's rotation.
This problem is very hard. I try to get a = [tex]\frac{2\pi(RcosL)^2}{T^2RcosL}[/tex] and then must get F so I try to separate the thingie into components byut then Fx and Fy get into a mess and I'm confused. Help!
Thanks
This problem is very hard. I try to get a = [tex]\frac{2\pi(RcosL)^2}{T^2RcosL}[/tex] and then must get F so I try to separate the thingie into components byut then Fx and Fy get into a mess and I'm confused. Help!
Thanks