- #1
joex444
- 44
- 0
Idk if this is right
[tex] e^{n^2} = (e^n)^n [/tex]
Atleast I didn't think [tex] e^{n^2} = e^n*e^n [/tex]
I had a test in calc 3 today, and that was part of a series. If it is equal (in the first equation) then I did it right, otherwise not. I came up with convergent, and someone else said they used an integral and got convergent, so...my answer hinges on that, which i should really know by now :)
[tex] e^{n^2} = (e^n)^n [/tex]
Atleast I didn't think [tex] e^{n^2} = e^n*e^n [/tex]
I had a test in calc 3 today, and that was part of a series. If it is equal (in the first equation) then I did it right, otherwise not. I came up with convergent, and someone else said they used an integral and got convergent, so...my answer hinges on that, which i should really know by now :)
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