How do I turn a parabolic curve into a straight line?

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In summary, the conversation discusses how to turn a half parabolic curve into a straight line. The proposed solution involves finding the gradient of the curve at a given point, using the derivative formula, and solving for the equation of the line using the given point and gradient. The speaker emphasizes the importance of understanding differentiation in order to solve these types of problems.
  • #1
twenty5
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sooper easy question :)

uhmm, say I have half of a parabolic curve, how do I turn it into a straight line?

what I'm thinking...

y = x2
root of y = x? but I leave the x as it is?

hmm hard to explain... let me try explaining a bit

(x,y)
(4,16)

okay? ok now to make it straight, I would do root of 4 and leave x as 16 and then just plot this on graph?

result

(x,y)
(2,16)

or would I do the root of 16 as well
 
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  • #2


I have to ask, what are you trying to do?

"uhmm, say I have half of a parabolic curve, how do I turn it into a straight line?"

That doesn't really make sense.. Are you trying to find the gradient of the curve at a point?
 
  • #3


Yeah i think he is;

First off you must differentiate, I'm not sure if you know what this means so i'll put a simple version down anyway;

y = x²

So CHANGE in y / CHANGE in x (gradient) = 2x (bring the power down)

Then insert the x figure

so say at the point x = 4, the gradient would be 8. (If you don't understand differentiation, look it up, it is KEY!! to understanding / doing any of these questions) http://en.wikipedia.org/wiki/Derivative

Then you must use the formula

y - y1 = g ( x - x1) Where you insert G gradient, y1 & x1, the points so

y - 16 = 8 (x - 4)

y = 8x + 12 Would be the equation for the line at the point x = 4

I can understand why you might find all that a bit hard to understand, if you still can't pickup on some stuff here post again! You must understand these problems! Peace! :P
 

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