Hi my question is whether an SOP = POS for a given function F(A, B, C, D). Or is the SOP a complement of POS?
Tasked to convert derive a simplfied SOP from a 4 var Kmap with dont cares.
My answer was,
F = C'.D' + A'.B'.C which is correct.
Then for part B they asked for the simplified POS form.
The Attempt at a Solution
F = C'.D' + A'.B'.C
F' = (C'.D' + A'.B'.C)' (Using Dmorg)
F' = ((c+d)' + (a+b+c')')' (Using Dmorg)
F' = (c+d)'.(a+b+c')'
F = ((c+d)'.(a+b+c')')'
F = (c+d) +(a+b+c') (Stuck here)
If i used Kmap i got the answer which is
I wanna know the boolean algebra way