1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Sound in phase

  1. Dec 4, 2005 #1
    Two speakers produce a 162Hz sound in phase. If an intensity minimum is located 3.75m from the nearer speaker, find the distance to the further speaker if the speed of sound in the air is 345m/s.

    Would it go like this
    d(1)-d(2)/wavelength=phase difference/2pi
    x-3.75/2.13=1/2pi
    x=4.09m

    This doesn't seem quite right let me know what to do please.
     
  2. jcsd
  3. Dec 5, 2005 #2

    Andrew Mason

    User Avatar
    Science Advisor
    Homework Helper

    The difference in distance must equal a multiple of half a wavelength for a minimum (phase difference = [itex]n\pi[/itex] not [itex]2n\pi[/itex]).

    AM
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?