What fraction of the acoustic power of a noise would have to be eliminated to lower its sound intensity level from 90 to 70dB?
I = Power/Area
B = 10 * log *(I/I0)
I0 = 10-12W/m2
The Attempt at a Solution
The answer I got for this is that the new power is 1% of the original. Which I don't think is true. A nudge in the right direction would be appreciated