# Sound Intensity level problem

## Homework Statement

What fraction of the acoustic power of a noise would have to be eliminated to lower its sound intensity level from 90 to 70dB?

## Homework Equations

I = Power/Area
B = 10 * log *(I/I0)

I0 = 10-12W/m2

## The Attempt at a Solution

The answer I got for this is that the new power is 1% of the original. Which I don't think is true. A nudge in the right direction would be appreciated

You can just solve $B = 10 * log (I/I_0)$ for I with B=90 and B is 70
You can just solve $B = 10 * log (I/I_0)$ for I with B=90 and B is 70