[SOLVED] Sound Intensity Please help!!! 1. The problem statement, all variables and given/known data The sound intensity level 5.0m from a point source is 95 dB. At what distance will it be 75 dB? 2. Relevant equations dB = 10log(I/Io) I = P/4*pi*r^2 3. The attempt at a solution I honestly don't know what to do with this problem. I started out by plugging 5.0m and 95 dB into the equation >> dB = 10log((P/4*pi*r^2)/Io) >> 95 = 10log((P/4*pi*25)/1*10^-12) >> 95 =10log(P/4*pi*25)-10log(1*10^-12) >> 95 + 10log(1*10^-12) = 10log(P/4*pi*25) >> -25 = 10log(P)-10log(4*pi*25) >> -25+10log(4*pi*25) = 10log(P) >> -.0307 = 10log(P) >> -.00307 = log(P) >> P = 10^-.00307 After that, I used the P that I found in the equation >> 75 = 10log((10^-.00307/4*pi*r^2)/1*10^-12) >> 75 + 10log(1*10^-12)=10log(10^-.00307/4*pi*r^2) >> -45 = 10log(10^-.00307)-10log(4*pi*r^2) >> -44.95 =-10log(4*pi)+10log(r^2) >> -33.96 = 10log(r^2) >> -3.39 = log(r^2) >> r^2 = 10^-3.39 >> r = .0200 This doesn't make any sense at all, but I don't know what I'm doing wrong. Our physics teacher didn't teach us the lesson on this. He just gave us a bunch of formulas and told us to figure it out. Am I using the wrong formulas, or am I making a stupid math error? Please help!!!