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Sound intensity

  1. Sep 16, 2015 #1
    1. The problem statement, all variables and given/known data
    If you install special sound-reflecting windows that reduce the sound intensity level by 35.0 dB , by what factor have you reduced the sound intensity?
    2. Relevant equations
    Δβ=10Log(I/I°)

    3. The attempt at a solution
    I°=10^-12
    I=I°-35
    35=10^1.5440680
    (I/I°)={(10^-12)-(10^1.5440680)}/{10^-12} =-3.5*10^13
    But this is wrong
     
    Last edited by a moderator: Sep 16, 2015
  2. jcsd
  3. Sep 16, 2015 #2

    berkeman

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    Staff: Mentor

    Welcome to the PF.

    I didn't follow some of what you did. Instead, start with substituting the -35dB into your first Relevant Equation:

    -35dB=10Log(I/I°)

    Now show the steps you use to solve for the fraction I/Io... :smile:
     
  4. Sep 16, 2015 #3
    -3.5=log(I/I°)
    10^-3.5=(I/I°)
    but still wrong
     
  5. Sep 17, 2015 #4

    berkeman

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    Staff: Mentor

    It should be right, IMO. Do you get about 1/3162 as the answer?
     
  6. Sep 17, 2015 #5

    berkeman

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    Staff: Mentor

    Maybe the answer is supposed to be stated as "reducing the sound intensity by a factor of 3162..."?
     
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