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Here is the original question:

Consider the space curve r(t) = (e^t)*cos(t)i + (e^t)*sin(t)j + k. Find the unit tangent vector T(0) and the curvature of r(t) at the point (0,e^(pi/2),1).

I believe I have found the unit tangent vector, T(0), correctly: (1/sqrt(2))i + (1/sqrt(2))j

Is this correct? Also, how do I find the curvature at that particular point?

Thanks!

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# Space Curves -> Unit Tangent Vector and Curvature

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