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Thanks!

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- #1

- 19

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Thanks!

- #2

Matterwave

Science Advisor

Gold Member

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- #3

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Thanks! A little confused why you referred to ##ds^2## as a scalar. Isn't it a four-vector?

- #4

bapowell

Science Advisor

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Nope. It's the scalar product of (differential) four-vectors.Thanks! A little confused why you referred to ##ds^2## as a scalar. Isn't it a four-vector?

- #5

Matterwave

Science Advisor

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Thanks! A little confused why you referred to ##ds^2## as a scalar. Isn't it a four-vector?

Why would it be a 4 vector? What are the 4 components that you are thinking of? It is a scalar because it's just 1 single number, which does not change under an arbitrary Lorentz transformation.

- #6

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Got it now. Thanks very much.

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