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Special Relativity of electrons

  1. Jun 1, 2009 #1
    1. How close would two stationary electrons have to be positioned so that their total mass is twice what it is when the electrons are very far apart?


    2. p = (mv) / (squareroot(1-(v2/c2))
    E = (mc2) / (squareroot(1-(v2/c2))
    E = mc2
    m = (rest mass) / (squareroot(1-(v2/c2))
    L = (proper length)*(squareroot(1-(v2/c2))


    3. m = 2(rest mass)
    m = (rest mass) / (squareroot(1-(v2/c2))
    v = 6.75 * 1016


    I solved up to the velocity but I don't know how to calculate the distance.



    1. A spacecraft approaching the earth launches an exploration vehicle. After the launch, an observer on earth sees the spacecraft approaching at a speed of 0.50c and the exploration vehicle approaching at a speed of 0.70c. What is the speed of the exploration vehicle relative to the spaceship?

    2. u = (u' + v) / (1 + (u;v/ c2))
    u' = (u - v) / ( 1- (uv/c2))


    3. I attempted this problem by setting u' equal to each other (each u either represents the exploration vehicle or the spaceship). But, I got stuck. I didn't know which v was for which vehicle/spaceship.
     
  2. jcsd
  3. Jun 1, 2009 #2

    Andrew Mason

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    The electrical potential energy has to equal 2me2. What is the expression for that potential energy in terms of distance between the electrons?


    Use http://hyperphysics.phy-astr.gsu.edu/hbase/relativ/einvel.html#c1"

    AM
     
    Last edited by a moderator: Apr 24, 2017
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