- #1

- 27

- 0

## Homework Statement

A girl is riding a bicycle along a straight road at constant speed, and passes a friend standing at a bus

stop (event #1). At a time of 60.0 s later, the friend catches a bus (event #2).

(a) In the frame of reference of the earth, what is the distance separating these events?

(b) If the distance separating the events is 126 m

**in the frame of the girl on the bicycle**, what is the

bicycle's speed?

## Homework Equations

v = d/t

## The Attempt at a Solution

For part a. d = vt where delta t (time) equals 60 seconds and I just left velocity as its variable so d = 60(v) so d = 60v

Part B where delta distance = 126m. This is where i start to run into problems. At first i thought the answer would be found using just v = d/t and what i did was v = 126m/60s which equals 2.1m/s. However, i think its incorrect because it asks for the velocity in the frame of reference of the girl on the bicycle. If anyone could clear this up it would be great. CORRECTION: it actually says the DISTANCE separating the events is 126m in the FRAME OF THE GIRL ON THE BYCYCLE. Would This still change my results?

Last edited: