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Special Relativity Spaceship Question
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[QUOTE="Lucille, post: 4872824, member: 524584"] [h2]Homework Statement [/h2] bob and anna are in two space ships of proper length 100m; anna's ship passes bob's and is moving in the -x dir at v=0.75c. the front of anna's ship and the tail of bob's ship coincide at x=x'=t=t'=0. bob sits at the window in his ship and sees a clock inside anna's ship a) what position is the window in bob's space ship b) what time does this clock in anna's ship read [h2]Homework Equations[/h2] x'=gamma(x-vt) x=gamma(x'+vt') t'=gamma(-v/c^2*x+t) t=gamma(v?c^2*x+t') delta t = gamma delta to L = Lo/gamma [h2]The Attempt at a Solution[/h2] a) so if bob sees the clock at the end of anna's ship, then: L=Lo/gamma = sqrt(1-v^2/c^2)*Lo = sqrt(1-0.75^2)*(100)=66.1m <-- position of bob's window in his spaceship (distance from the end of his spaceship to the window) b) i tried : x=100m v=0.75c t'=x'/v = 4.45 * 10^-7 s But I'm not sure if this is correct... [/QUOTE]
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