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Special relativity - spaceship speed and position

  1. Oct 23, 2008 #1
    Hi,

    a friend today teased me with the following SR problem. I worked out a solution
    but I'm not so confident about my SR. Should I better brush up on it?

    1. The problem statement, all variables and given/known data

    So there's this spaceship traveling at some unknown constant speed, getting away from Earth. It has two mirrors on it, one at the front and one at the rear.
    Earth sends two simultaneous light pulses which are reflected by the two mirrors
    and get back to Earth after times 2 T1 and 2 T2.
    Knowing these times and the length L of the spaceship we should evaluate the
    speed v and the distance of the spaceship (say at the time we receive the second signal).

    2. Relevant equations

    The only tricky point is time dilation, in my opinion.

    3. The attempt at a solution

    So this is what I would do to determine the speed v. When this is known the distance would simply be d = T2 (c + v).

    I'd say that the first pulse hits the rear mirror at time T1. At this time the second pulse is at the rear of the ship as well. This second pulse hits the front mirror at time T2, so that t = T2-T1 is the time it takes to go from the rear to the front of the ship.
    All of this in the reference frame of the earth.
    Now from the point of view of the spaceship the second pulse takes a time t' = L/c in covering the length of the ship. The times t and t' should be related by time dilation:

    t = t' / sqrt(1-v^2/c^2).

    In summary I get

    (T2-T1)^2 = L^2/(c^2-v^2)

    which can be solved for v.


    Seems correct to me, but my friend and other people put forward tricky arguments and I'm not sure any more of my solution.

    Thanks
     
  2. jcsd
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