# Special relativity

## Homework Statement

I have the trajectories of a particle in the space-time:

$$\tau$$($$\sigma$$) = $$\frac{1}{a}$$senh($$\sigma$$)

x($$\sigma$$) = $$\frac{1}{a}$$cosh($$\sigma$$)

How can I write this equations depending on proper time t of the particle?

## The Attempt at a Solution

sylas
How can I write this equations depending on proper time t of the particle?

Start out by defining the proper time. If you have a trajectory for a particle, what is the proper time along that trajectory, in general?

The proper time is :

t = $$\int\sqrt{1-\frac{1}{c^{2}}(\frac{dx}{dt})^{2}}$$dt

sylas
The proper time is :

t = $$\int\sqrt{1-\frac{1}{c^{2}}(\frac{dx}{dt})^{2}}$$dt

Good... now how can you get dx/dt?

By the way; you are being a bit unusual with your variable names. You have "t" being used above both as proper time (on the LHS) and as co-ordinate time (on the RHS, inside the integral).

It's more usual to use τ (Greek tau) as the proper time. In your original post, you also use tau as the co-ordinate time.

Maybe I can write :

$$\frac{dx}{dt}$$ = $$\frac{dx}{d\sigma}$$ * $$\frac{d\sigma}{dt}$$

Where :

t : co-ordinate time

$$\tau$$ : proper time

PS: you are right!!
In my original post : $$\tau$$ $$\rightarrow$$ t
In my second post : t $$\rightarrow$$ $$\tau$$ (in the first member)

sylas
OK... there's another thing.

In your original equations, there's no mention of "c". Were your original equations given in units where c=1? This is commonly done to keep it simple.

To use your definition of proper time, where c is explicit, you'll have to make a small change to one of your original equations... or (easier) let c=1 in your definition of proper time and keep in mind that your units have this property.

My prof gave me those equations without "c". I think that I must continue in units where c=1. Maybe in my definition proper time I have to put c=1.

sylas
My prof gave me those equations without "c". I think that I must continue in units where c=1. Maybe in my definition proper time I have to put c=1.

You are now well on the way to a solution. Let me give you a hint, however. When you do the integration, try changing the integration variable to σ. That is, replace "dt" with $$\frac{dt}{d\sigma} d\sigma[/itex] What this gives you, in fact, is the parametrized definition of proper time. It will work a bit more easily, since everything is now in terms of σ in your equations. Ok, so I write : [tex]\tau$$ = $$\int\sqrt{\frac{dt^{2}}{d\sigma^{2}}-\frac{dx^{2}}{d\sigma^{2}}}$$ d$$\sigma$$

and I can solve the integral. So I get $$\tau$$ in function of $$\sigma$$

But How can I write t and x in function of $$\tau$$ ?

sylas
Ok, so I write :

$$\tau$$ = $$\int\sqrt{\frac{dt^{2}}{d\sigma^{2}}-\frac{dx^{2}}{d\sigma^{2}}}$$ d$$\sigma$$

and I can solve the integral. So I get $$\tau$$ in function of $$\sigma$$

But How can I write t and x in function of $$\tau$$ ?

Try it. Solve the integral. It's going to be surprisingly easy.

PS. When you use LaTeX, put the whole equation inside the {tex} {/tex} tags. It will look much nicer!

I found :

$$\tau$$ = $$\int$$ $$\sqrt{1/a^{2}}$$ d$$\sigma$$ = $$\frac{\sigma}{a}$$

So I have to replace $$\sigma$$ with a*$$\tau$$ in my original equations.
Is it right?

sylas
I found :

$$\tau$$ = $$\int$$ $$\sqrt{1/a^{2}}$$ d$$\sigma$$ = $$\frac{\sigma}{a}$$

So I have to replace $$\sigma$$ with a*$$\tau$$ in my original equations.
Is it right?

Yes. In fact, your original equations are almost given in terms of proper time already! They are standard parametric equations for constant proper acceleration. That is, a particle following this world line experiences the same fixed acceleration all the time.

Yes, infact in the next part of the exercise I have to demonstrate the proper acceleration is costant and =a!
thank you very much!!

sylas