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## Homework Statement

Calculate the energy need to change 9 g of ice at -20 degrees Celsius to steam at 110 degrees Celsius. (C for ice=2.06 J/g, C for water=4.18 J/g, C for steam=2.02 J/g, Hf of ice=334 J/g, Hv of water=2260 J/g)

## Homework Equations

Q=hv / Q=mHf / Q=mc(delta)t

## The Attempt at a Solution

Q=(9 X 2.06 X 20) + (9 X 334) + (9 X 2.06 X 110) + (9 X 2260) + (9 X 2.06 X 110) = 27795 J

Okay so I did this problem in class with a group, but looking back on it, I think it is wrong. But I'm not sure! I'm just very very very confused on what to do. Step by step instructions would help!! And the answer has to be in joules not calories. Thanks!! :)