This is a really simple problem, but I just can't remember how to combine the container and the water.(adsbygoogle = window.adsbygoogle || []).push({});

1. The problem statement, all variables and given/known data

An aluminum container weighing 200g contains 500g of water at 20*c. A 300g shot of the same aluminum at 100*c is put into the water. The specific heat for the aluminum is 0.215cal/(g*c). What is the final temperature for the entire system?

2. Relevant equations

dQ = c*m*dT

3. The attempt at a solution

(T - 20*c) x [(500g x 1cal/(g*c)) + (200 x 0.215cal/(g*c))] = (T - 100*c) x 300g x 0.215cal/(g*c)

T = 9.1216*c

However this answer seems really off.

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Specific Heat and aluminum

**Physics Forums | Science Articles, Homework Help, Discussion**