How much ice was added to a 0.75 kg jug of lemonade at 15 degrees celcius if the final temperature of the jug is 8 degrees celcius? (Assume the lemonade has the specific heat capacity of water.)
Q = cm∆T
The Attempt at a Solution
Well I think I might have to rearrange Q = cm∆T to solve for mass, so m = Q/c*∆T. But I don't have the heat, and then how would I account for the mass of the jug? Help!!