1. The problem statement, all variables and given/known data A 30.0g block of ice at 0.00°C is dropped into 500.0g of water at 45.0°C. If the process was carried out in an iron container with a mass of 150g what would the final temperature be? 2. Relevant equations Q=mc(T2-T1) Heat Lost = Heat Gained Specific Heat of Water: 4200 Specific Heat of Ice: 2100 Specific Heat of Iron: 460 3. The attempt at a solution I understand how to find the final temperature of the water without the iron container using the equation above (mc(T2-T1)=mc(T2-T1)) and i get (34.5 degrees), however i'm completely stuck when it comes to adding the iron mass into the equation.