3.00 kg of molten lead is allowed to cool until is has solidified. It is found that the temperature of the lead falls from 605 K to 600 K in 10 s, remains constant at 600K for 300 s, and then falls to 595 K in a further 8.4 s. Assuming that the loss of heat energy remains constant and the specific heat capacity of solid lead is 140 Jkg-1 K-1, calculate:
(a) the rate of loss of energy from the lead; ()
(b) the specific latent heat of fusion of lead; ()
(c) the specific heat capacity of liquid lead.
The Attempt at a Solution
No idea how to start this, can someone give me a hand to start please.