1.0 g of water at 28 degree celcius is placed into a 200g aluminium can at 300 degree celcius. What is the temperature of the aluminium can after all the water vapourises? Given the specific heat capacity of aluminium, 900 J/kg/degree celcius and water, 4200 and specific latent heat of water, 2.26 x 10^6 J/kg assuming no heat is loss to the surrounding.
The Attempt at a Solution
I am not sure how to go about when it comes to combined specific heat capacity. Do we simply add them up?