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Specific laplace transform

  1. Jan 27, 2009 #1
    There are lots of tables out there for finding the inverse laplace transform of:

    [tex]\frac{1}{(s+b)^{2}+a^{2}}[/tex]

    or

    [tex]\frac{s}{(s+b)^{2}+a^{2}}[/tex]

    but what if [tex]a^{2}[/tex] is negative?

    I don't know what useful formula I should split it up into.
     
  2. jcsd
  3. Jan 27, 2009 #2
    If a2 is negative then you may further factored the denominator. Then you formed a partial fraction for the whole expression.

    e.g. let a2=-c2.

    (s+b)2+a2=(s+b+c)(s+b-c)
     
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