1. The problem statement, all variables and given/known data from the following observations made during an experiment,determine the specific latent heat of vaporisation of water. initial mass of water 400g final mass of water 450g mass of calorimeter 200g initial temperature of water & calorimeter 16 degrees final temperature of water & calorimeter 70 degrees specific heat capacity of water 4200 j/kg degrees specific heat capacity of calorimeter 420 j/kg degrees 2. Relevant equations Q= m hfg 3. The attempt at a solution let suffix s = steam w = water and c = calorimeter -ms hfg = mw cw delta tw + mc cc delta tc + ms cw delta ts -50 = 400x4200x(70-16)+200x420x(70-16)+50x4200x(70-100)=88.956x10 6 therefore 50/88.956x10 6 = 562.075 x 10 -9 if someone would be so kind to check if this is right it will be much appreciated.