Calculating Melting Time for 7.5g Ice Cube at 0°C

[NabeelIshaq]

An ice-cube has a mass of 7.50 g. The ice-cube is at 0 °C.
Heat from the surroundings reaches the ice-cube at an average rate of 1.25 J / s.
How long does it take for all of the ice to melt?
(specific latent heat of fusion of ice = 333 J / g)
A 35.5 s B 55.5 s C 2000 s D 3120 s

 

[tiny-tim]

Welcome to PF!

Hi NabeelIshaq! Welcome to PF!

Show us what you've tried, and where you're stuck, and then we'll know how to help!

 

[123peo]

I NEED HELP ASAP PLEASE!
DOES ANYONE KNOW THE METHOD OR WHAT THIS EXPERIMENT IS CALLED? ALL I KNOW IS IT IS TO DO WITH ELECTRICITY. ALSO YOU USE THE FORMULA OF ITV X 150
PLEASE HELP the image that I have of the experiment is in the link below THANK YOU

http://tap.iop.org/energy/thermal_physics/page_40505.html

 

[JaredJames]

Writing in block capitals doesn't get more attention.

I recommend you start your own thread to gain a better response.

Jared

 

[sardar]

Based on the given information, we can use the formula Q = mL to calculate the amount of heat required to melt the ice cube. Q represents the heat energy, m is the mass of the ice cube, and L is the specific latent heat of fusion of ice.

In this case, Q = (7.5 g) x (333 J/g) = 2497.5 J

Next, we can use the formula t = Q / P to calculate the time it takes for all the ice to melt, where t is the time, Q is the heat energy calculated above, and P is the average rate of heat transfer from the surroundings, which is 1.25 J/s.

Therefore, t = (2497.5 J) / (1.25 J/s) = 1998 seconds or approximately 33.3 minutes.

Therefore, the correct answer is C) 2000 seconds. It would take approximately 33.3 minutes for all of the 7.5g ice cube to melt at 0°C with an average heat transfer rate of 1.25 J/s.