(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A rocket is launched straight up from the earth's surface at a speed of 15,000 m/s. What is its speed when it is very far away from earth?

2. Relevant equations

K=.5mv^2

U=-GMm/R

3. The attempt at a solution

Is this correct: I used conservation of energy and assumed very far was where U=0

(.5)(m)(15000m/s)^2 + -[(6.67*10^-11)(5.98*10^24)m]/[6.37*10^6m)=.5mv^2

v=9988 m/s

Also could someone explain to me why potential energy decreases with increasing height in this case as opposed to increasing U by lifting an object above the ground on earth.

Thanks

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# Homework Help: Sped of launchin rocket

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