# Speed after acceleration

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1. Sep 19, 2016

### nick4945

1. The problem statement, all variables and given/known data
A particle at rest undergoes an acceleration of 2.7 m/s2 to the right and 4.3 m/s2 up.
-What is its speed after 6.8 s?
-What is its direction with respect to the horizontal at this time?
-Answer between −180◦ and +180◦ .
-Answer in units of ◦ .

2. Relevant equations

3. The attempt at a solution
I don't even know where to start

2. Sep 19, 2016

### hmmm27

You could start with what you do know, and find out things you don't.

Do you think "2.7 m/s2 to the right and 4.3 m/s2 up" means the particle is zig-zagging ?
Are you familiar with the Pythaogrean Theorem ?
Do know how to calculate speed, given an acceleration ?
Do you know the simple trigonometry definitions

Last edited: Sep 19, 2016
3. Sep 20, 2016

### Kaura

See if there is a kinematic equation to calculate velocity after time given acceleration
If you have both the horizontal and vertical vector components of velocity then see if you can solve for total magnitude of velocity
It might help to think of the two vector components as sides of a right triangle