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an object mass of .5kb revovles uniformly in cirlce horizontal frictionless surface. it is attached by .75 m cord to pin set in surface. if object makes 2 complete revolujtions per second, find its speed and its centripetal force
mg = m(v2/r)
gr = v2
v = sq root of gr
v = sq root of 9.8*.75
v = 2.7 m/s2
anyone wanna do me a favor, and check if i'm doing' this right,
thanks a lot..
mg = m(v2/r)
gr = v2
v = sq root of gr
v = sq root of 9.8*.75
v = 2.7 m/s2
anyone wanna do me a favor, and check if i'm doing' this right,
thanks a lot..