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Speed and its centripetal force of circling object

  • Thread starter bigman8424
  • Start date
25
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an object mass of .5kb revovles uniformly in cirlce horizontal frictionless surface. it is attached by .75 m cord to pin set in surface. if object makes 2 complete revolujtions per second, find its speed and its centripetal force

mg = m(v2/r)
gr = v2
v = sq root of gr
v = sq root of 9.8*.75
v = 2.7 m/s2

anyone wanna do me a favor, and check if i'm doing' this right,
thanks a lot..
 

Andrew Mason

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bigman8424 said:
an object mass of .5kb revovles uniformly in cirlce horizontal frictionless surface. it is attached by .75 m cord to pin set in surface. if object makes 2 complete revolujtions per second, find its speed and its centripetal force

mg = m(v2/r)
gr = v2
v = sq root of gr
v = sq root of 9.8*.75
v = 2.7 m/s2

anyone wanna do me a favor, and check if i'm doing' this right,
thanks a lot..
Gravity has nothing to do with this problem. The centripetal force is mv^2/r. All you have to do is work out what v is from:

[tex]v = 2\pi r/T[/tex] where T = .5 sec.

AM
 

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