Sam, whose mass is 75 kg, stands at the top of a 12-m-high, 100-m-long snow-covered slope. His skis have a coefficient of kinetic friction on snow of 0.07. If he uses his poles to get started, then glides down, what is his speed at the bottom?
v = √(2g(h-μk√(L2-h2)))
The Attempt at a Solution
It seems as simple as plugging in the values into the equation, but my result isn't anywhere near what it should be.
From my understanding:
g = 9.8
h = 12m
L = 100m
μk = 0.07
v = √(2(9.8)(12-0.07√(1002-122))) = 152.36
152.36 m/s? That seems a bit much to me. The back of my book says that it is 9.9 m/s, but how do I get there?
What did I mess up on?