Mitch throws a 100 g lump of clay at a 500 g target, which is at rest on a horizontal surface. After impact, the target, including the attached clay, slides 2.1 m before stopping. If the coefficient of kinetic friction is [tex]\mu[/tex]k = 0.35, find the speed of the clay before impact. I don't know where to start in this problem. I know that the equation for kinetic friction is fk = [tex]\mu[/tex]kn but I don't know what the normal force is. My only thought would be that n = mg, which means it would be .6 kg (5g + 1g = 6g). Is that correct? Any help would be appreciated. Please be detailed with each step, because I need to understand it and be able to show my work.