Speed in Larger and Smaller Tube

  • Thread starter MoBaT
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  • #1
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Homework Statement


A constricted horizontal tube of radius r1 = 4.00cm tapers to a tube of radius r2 = 2.50cm. If water flows at a speed 3.50m/s in the larger tube, (A) find its speed in the smaller tube. (b) Find the water pressure difference ΔP=ΔP1-ΔP2 in kPa and in atm.


Homework Equations



I have no clue.

The Attempt at a Solution



Succeeded in doing part A.

A1V1 = A2V2

V2 = (A1V1)/A2 = (pi(4)^2(3.50)) / (pi(2.50)^2) = 8.96 m/s
 
Last edited:

Answers and Replies

  • #2
Simon Bridge
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Venturi effect?
 
  • #3
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You need to use Bernoulli's principle . The water speeds up and therefore gains KE.
This gain in KE comes from a decrease in PE (pressure)

ΔP = 0.5ρ(v2^2 - v1^2) ρ = density of water
(this is bernoulli's principle in its simplest form with the tube horizontal)
 
Last edited:

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