A 12 g bullet is fired into a 8.0 kg wood block that is at rest on a wood table. The block, with the bullet embedded, slides 5.0 cm across the table. The coefficient of kinetic friction for wood sliding on wood is 0.20. What was the speed of the bullet? Relevant equations My professor told us that we would need these equations: (1/2)mv2 = mgx mvi = (m1+m2)v2 The attempt at a solution v2 = 2(9.81)(0.20)(0.05) v = 0.443 0.012vi = (8.0+0.012)(0.443)2 vi = 131 m/s This seemed like a logical process and the answer seemed fairly reasonable (bullets move fast) however, this is not the right answer and I don't know what I am doing wrong.