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Speed of a Potted Plant

  1. Oct 25, 2011 #1
    1. The problem statement, all variables and given/known data
    [PLAIN]http://img8.imageshack.us/img8/664/photo4dc.jpg [Broken]
    Sorry it is sideways.

    Only known data is the 6m drop from the 12m high ledge.
    2. Relevant equations

    Currently wokring with Kinetic enery (1/2mv^2), potential energy(mgh).

    3. The attempt at a solution

    My thinking is mass doesnt matter, it will cancel out due to the mechanical energy( if that makes sense). Therefore the equation to solve is v2f=2gh

    Therefore after subbing in 9.81m/ss for g, 6m for h; my final answer is 11m/s with rounding because of sig figs.

    Thank you for help
     
    Last edited by a moderator: May 5, 2017
  2. jcsd
  3. Oct 25, 2011 #2

    phinds

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    Gold Member
    2016 Award

    Uh, do you think you could make that figure a little bigger ... I mean, I can almost see 25% of it at a time as it is.
     
  4. Oct 25, 2011 #3
    I also got 11m/s, but found that answer in a less complicated way:

    You know:
    velocity_initial is 0m/s
    Distance is 6m
    Acceleration is 9.8m/ss

    So:
    velocity_final= SQRT(2*A*D)
    V_F= SQRT(2*9.8*6)
    V_F= 10.844m/s
     
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