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Homework Help: Speed of a proton at triumf

  1. Feb 10, 2009 #1
    1. The problem statement, all variables and given/known data
    Determine the speed of a proton whose kinetic energy is 500 MeV. The mass of a proton is 938.27 MeV/c2.


    2. Relevant equations
    K = (1/2)mv2??



    3. The attempt at a solution
    The correct answer is supposed to be 0.758c, where c is the speed of light.
    Of course, I plugged in the given numbers to the equation and got the wrong answer 1.0323 c. What did I do wrong? What does it mean by "triumf"?

    Thanks
     
  2. jcsd
  3. Feb 10, 2009 #2

    Kurdt

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    Staff Emeritus
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    Gold Member

    You will need to use special relativity to tackle this problem. Triumf is just a particle accelerator.
     
  4. Jan 28, 2010 #3
    The formula KE = (gamma -1)mc^2 may be helpful for your endeavors.
    where gamma = (1-v^2/v^2)^(-1/2)
     
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