Speed of Pivoting Rulers

  • Thread starter ljetoxox
  • Start date
  • #1
1
0
1. A .200 kg stick pivots about one end. The meter stick starts balanced above this pivot. What would be the speed of the center of mass of the meter stick at the bottom of the swing?



2. Torque=force sin (theta)*radius


3. The torque acting on the object is .981 N*m (9.81*.2*sin 90*.5) (sin 90 because it is 90 degrees above the horizontal axis.)
But how do you get angular velocity from torque? I also know that torque=moment of intertia*angular acceleration. But how do you get angular velocity from this?
Is this even a torque problem?
 

Answers and Replies

  • #2
Hootenanny
Staff Emeritus
Science Advisor
Gold Member
9,621
6
Welcome to Physics Forums,

You can indeed solve this problem by considering the torques acting on the ruler. However, it may be somewhat simpler to consider conservation of energy.
 

Related Threads on Speed of Pivoting Rulers

Replies
4
Views
6K
  • Last Post
Replies
12
Views
3K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
2
Views
5K
  • Last Post
Replies
7
Views
1K
  • Last Post
Replies
9
Views
2K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
1
Views
3K
  • Last Post
Replies
9
Views
4K
Top