Speed of sound in a gas mixture

In this case, we have two gases, argon and neon, with respective mole fractions x1 and x2 and speeds of sound v1 and v2. By plugging in the values given in the problem, we can solve for x1 and x2 and then calculate the percentage of argon and neon atoms in the mixture.In summary, the problem involves finding the percentage of argon and neon atoms in a mixture of argon and neon gases at a certain temperature where the speed of sound is given. The equation used to solve the problem is derived from the relation between the speed of sound in a mixture of gases and the mole fractions and speeds of sound of each individual gas in the mixture. By plugging in the given values,
  • #1
Rick4
2
0
In a mixture of argon (atomic mass = 39.9 u) and neon (atomic mass = 20.2 u), the speed of sound is 363 m/s at 300K. Assume that both monatomic gases behave as ideal gases. Find the percentage of the atoms that are argon and the percentage that are neon.

I found the solution (in the attachments) but what I can't figure out is where the equation that was used in step 4 of the solution came from.

This is the equation that was used to solve the problem.
Where did it come from?

v = (v1v2(V1+ V2)1/2)/(V2v12 + V1v22)1/2
 

Attachments

  • Step 1 & 2.jpg
    Step 1 & 2.jpg
    27.1 KB · Views: 829
  • Step 3 & 4.jpg
    Step 3 & 4.jpg
    35.6 KB · Views: 973
  • Step 5 & 6.jpg
    Step 5 & 6.jpg
    13.3 KB · Views: 729
Physics news on Phys.org
  • #2
The equation is derived from the fact that the speed of sound in a mixture of gases is given by the following relation: v = (∑xivi)1/2, where xi is the mole fraction of gas i and vi is the speed of sound in gas i.
 
  • #3


The equation used in step 4 of the solution is known as the root-mean-square (rms) velocity formula for gases. It is derived from the kinetic theory of gases and is used to calculate the average speed of gas molecules in a mixture. The equation takes into account the individual velocities and masses of the gas molecules in the mixture. In this case, the equation is used to calculate the speed of sound in the gas mixture, which is related to the average speed of the gas molecules.
 

1. What factors affect the speed of sound in a gas mixture?

The speed of sound in a gas mixture is affected by several factors, including the temperature, pressure, and composition of the gas. The speed also varies with the molecular weight and the density of the gas mixture.

2. How does the speed of sound in a gas mixture compare to the speed of sound in a pure gas?

The speed of sound in a gas mixture is generally lower than the speed of sound in a pure gas. This is because the different gases in the mixture have different molecular weights and densities, which can affect the overall speed of sound.

3. Can the speed of sound in a gas mixture be calculated?

Yes, the speed of sound in a gas mixture can be calculated using the ideal gas law, which takes into account the temperature, pressure, and molar mass of the gases in the mixture. Alternatively, it can also be measured using specialized equipment.

4. How does the speed of sound in a gas mixture change with temperature and pressure?

As the temperature and pressure of a gas mixture increase, the speed of sound also increases. This is because the molecules in the gas are moving faster and colliding more frequently, which increases the speed of sound waves through the gas mixture.

5. Why is the speed of sound in a gas mixture important to study?

The speed of sound in a gas mixture is an important factor to consider in various fields, such as acoustics, aerospace engineering, and atmospheric science. It helps us understand how sound propagates through different gases and how it can be affected by different factors, which can have practical applications in various industries.

Similar threads

  • Introductory Physics Homework Help
Replies
16
Views
2K
  • Introductory Physics Homework Help
Replies
7
Views
858
Replies
3
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
19
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
6
Views
4K
  • Introductory Physics Homework Help
Replies
11
Views
2K
  • Introductory Physics Homework Help
Replies
2
Views
1K
Back
Top