What are the speeds of molars and premolars going down in a compression test?

[marialaarni18]

Homework Statement

How to calculate for the speed of molars and premolars going down. Lower jaw is stationary or don't move. Only the upper jaw, goes down. Upper jaw and lower jaw are connected by a pivot. The jaw was attached (the upper and lower part ) in the instron machine, with a load (2000 N) going down that pushes the upper jaw downwards. What parameters should I measure in order to derive this?

Homework Equations

Given:
distance between the pivot and premolars= 78.3 mm
distance between the pivot and molars= 56.5 mm

The Attempt at a Solution

I also measured the following:
distance between upper and lower molar= 21.85 mm
distance between upper and lower premolars= 23.23 mm

I conducted compression test with compression rate of 1 mm/sec
length of time of closure of molars= 33.03 sec
length of time of closure of premolars= 26.25 sec

 

[jbsteele]

Using the data above, I calculated the speed of the molars and premolars going down. The speed of the molars going down is calculated by: Speed of molars = (distance between upper and lower molar / time of closure of molars) x compression rate Speed of molars = (21.85 mm / 33.03 sec) x 1 mm/secSpeed of molars = 0.66 mm/sec The speed of the premolars going down is calculated by: Speed of premolars = (distance between upper and lower premolars / time of closure of premolars) x compression rate Speed of premolars = (23.23 mm / 26.25 sec) x 1 mm/secSpeed of premolars = 0.88 mm/sec