Speed of the Electron

  • Thread starter LukasMont
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  • #1
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Good evening!

The question states: 9. Electron in bound orbit about proton. Suppose that an electron moves in a circular orbit about a proton at a distance of 2 X l0^-8 cm. Consider the proton to be at rest. (a) Solve for the velocity of the electron by equating the centrifugal and electrostatic forces.

Considering that the elementary charge (charge of the electron is e = 4.8 x 10^-10 statcoloumbs), working on the cgs system, I equated the centrifugal force Fc=v²/r and the eletrostatic force Fe= e²/r². My way of solving the problem was:

Fc=Fe,
v²/r = e²/r²
v²= e²/r
v= (e²/r)¹/²
v= (2.3x10^-19/2x10^-8)¹/²
v = 11.5x10^-6 cm/s.

Which is clearly a way down from the correct value. Could anyone please help me?

Thanks!
 

Answers and Replies

  • #3
mjc123
Science Advisor
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Also your last calculation step is wrong. v = (11.5x10-12)1/2 which is not 11.5x10-6. But see also Orodruin's comment.
 

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