- #1

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## Homework Statement

What's the speed and direction of the following wave(A,B and C are constants)

[tex]y(x,t)=Ae^{Bx^2+BC^2t^2-2BCxt}[/tex]

## The Attempt at a Solution

[tex]y(x,t)=Ae^{B(x-Ct)^2}[/tex]

from (x-Ct)

v=C in the +x direction

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- Thread starter azatkgz
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- #1

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What's the speed and direction of the following wave(A,B and C are constants)

[tex]y(x,t)=Ae^{Bx^2+BC^2t^2-2BCxt}[/tex]

[tex]y(x,t)=Ae^{B(x-Ct)^2}[/tex]

from (x-Ct)

v=C in the +x direction

- #2

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- #3

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No,it's original question.There's no imaginary constant.

So my solution is true.Thanks for checking.

So my solution is true.Thanks for checking.

- #4

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[tex]Ae^{i(x-vt)}[/tex]

Regular exponentials don't satisfy the wave equation. The wave equation says that two derivatives in time equal two derivatives in space divided by the velocity squared.

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