A cylindrical hole of radius R is drilled through the center of a sphere of radius 3. Use the method of cylindrical shells to find the volume of the remaining solid, given that the solid is 6 cm. high.
V= ∫2* ∏rh dr (shell method)
The Attempt at a Solution
I think this is the form to be used for this problem, but I am probably mistaken.
2 * ∫2* ∏ * x (R^2 - x^2) dx with a= r and b= R
4∏ ∫x (R^2 - x^2) dx
Then I'm stumped on how to do this :/ Thank you for your help.