Volume of Cone with Inscribed Sphere

In summary, a cone with a radius of 5 units is circumscribed around a sphere. The volume of the cone can be written in terms of x by using Pythagoras to find the radius and finding the height using the given information and the similarity of triangles. The angle at the vertex can be any value except for 0 or 180 degrees.
  • #1
zeion
466
1

Homework Statement



A cone is circumscribed around a sphere. The radius of the sphere is 5 units.
Write the volume of the cone in terms of x.
There is a diagram.. I will try to describe it:
It is a cross section of the object (sphere in cone). From the center of the circle to the bottom left vertice of the triangle is length 5 + x. (5 is the radius, x is the rest of the line).

Homework Equations


The Attempt at a Solution



So I can get r of the cone with Pythagoras = sqrt((x + 5)^2 - 25). The height would be 10 + something. I'm not sure how the missing part of the height relates to x.
 
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  • #2
The problem is that there are an infinite number of such cones. First draw a triangle circumscribing a circle (the sphere inside the cone seen from the side). Choose and angle for the vertex at the top of the sphere. That angle cannot be 0 or 180 degrees but it can be any other between. And then there exist a cone, having that angle at the vertex, circumscribing the sphere.
 
  • #3
So how can I write the volume in terms of x ?
 
  • #4
forumspherecone.jpg


I certainly wouldn't have chosen x as the main variable in this problem, but never mind that. Look at the figure. All you need to find the volume of the cone is its radius and height. So in the figure you need to get r and y in terms of x. r is easy from the right triangle AOB. Then you can get w + v in terms of y and x from triangle ABD. Then use the similarity of triangles ABD and DCO to get y in terms of x.
 

What is the "sphere inside a cone" question?

The "sphere inside a cone" question is a common physics problem that involves finding the volume of a cone that is filled with a spherical object, such as a ball or a marble. This problem is often used to test students' understanding of geometric concepts and their ability to apply mathematical formulas.

What are the steps to solving the "sphere inside a cone" problem?

The first step is to determine the radius of the cone's base and the radius of the sphere. Then, use the formula for the volume of a cone (V = 1/3πr²h) to find the volume of the cone. Next, use the formula for the volume of a sphere (V = 4/3πr³) to find the volume of the sphere. Finally, subtract the volume of the sphere from the volume of the cone to find the remaining volume of the cone.

What assumptions are made in the "sphere inside a cone" problem?

The "sphere inside a cone" problem assumes that the cone and the sphere are both perfectly symmetrical and that the sphere is completely contained within the cone without touching the sides or the base. It also assumes that the cone is not hollow and that the sphere is not filled with any other objects or material.

How is the "sphere inside a cone" problem relevant to real-life situations?

The "sphere inside a cone" problem is relevant to real-life situations because it can be used to calculate the volume of various objects, such as ice cream cones, traffic cones, and sports equipment. It also helps to develop critical thinking skills and problem-solving abilities, which are valuable in many scientific and engineering fields.

What are some common variations of the "sphere inside a cone" problem?

Some common variations of the "sphere inside a cone" problem include finding the height of the cone given the radius of the cone's base and the volume of the sphere, finding the radius of the sphere given the height and volume of the cone, and finding the surface area of the cone and the sphere. These variations can be more challenging and require a deeper understanding of geometric concepts and mathematical formulas.

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