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Spherical Capacitor

  • Thread starter mopar969
  • Start date
  • #1
201
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I need help on starting and solving this problem. See attachment for problem.

Homework Statement





Homework Equations





The Attempt at a Solution

 

Attachments

Answers and Replies

  • #2
ideasrule
Homework Helper
2,266
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Do you know Gauss' law?
 
  • #3
201
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yes.
 
  • #4
ideasrule
Homework Helper
2,266
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yes.
In that case, use Gauss' law to attempt this problem, and post your attempt here. We can't just give you the answers without some effort on your part towards a solution.
 
  • #5
201
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I know that gauss law says q over epsilon zero but how do I incorporate this for the dielectric material?
 
  • #6
201
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I know that the electric field for a dielectric is e = Q all over 4 pi k epsilon zero r^2. I also know that the electric field for the innerest conductor can be found using E = 1 over 4 pi epsilon zero time Q over r^2. Using this equation I got 3.25 x 10 ^ -9. However I do not know how to solve the outer most shell given with the charge per volume value. And for my dielectric electric field formula how do I get the er value of 1.8 that was given in the problem into the equation?
 
  • #7
201
0
Anybody have a way to solve this problem?
 

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