# Spherical conductor

## Homework Statement

Let's say I have :
Spherical conductor has a inner cubic cavity of side = b;
inside the cubic cavity we have a charge = y;
the surface of the sphere has a charge density = z;
I need to calculate the electric field at some point g, where g>r;

## Homework Equations

I believe we can say that the sphere is uniformly charged.

## The Attempt at a Solution

I don't need all of these information right?

All I do is

E= y/4*pi*E0*g2

?????

## The Attempt at a Solution

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G01
Homework Helper
Gold Member
HINT: This is a Gauss's Law problem. How much charge is enclosed by your Gaussian surface?

the charge enclose to the surface is just Q.

G01
Homework Helper
Gold Member
What do you mean by Q? Express the charge enclosed using the variables and quantities defined by the problem.

sorry i mean y.

so all i have to do for the outside electric field is:

y/4*pi*eog2

That's all i have to do right?

G01
Homework Helper
Gold Member
What about the charge density on the surface of the sphere? You need to take that into account.

i think this may work:

Electric field at point g=

(1/4*pi*eo)*∫ p d(tao)

= (1/4*pi*eo)*∫chargedensity(z) *radius(x)^2 * sin(theta) d(x) d(theta) d (phi)

will that work?