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Spherical conductor

  • Thread starter jackxxny
  • Start date
  • #1
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Homework Statement


Let's say I have :
Spherical conductor of radius=x;
Spherical conductor has a inner cubic cavity of side = b;
inside the cubic cavity we have a charge = y;
the surface of the sphere has a charge density = z;
I need to calculate the electric field at some point g, where g>r;


Homework Equations



I believe we can say that the sphere is uniformly charged.

The Attempt at a Solution



I don't need all of these information right?

All I do is

E= y/4*pi*E0*g2

?????

Homework Statement





Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
G01
Homework Helper
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HINT: This is a Gauss's Law problem. How much charge is enclosed by your Gaussian surface?
 
  • #3
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the charge enclose to the surface is just Q.
 
  • #4
G01
Homework Helper
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What do you mean by Q? Express the charge enclosed using the variables and quantities defined by the problem.
 
  • #5
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sorry i mean y.

so all i have to do for the outside electric field is:


y/4*pi*eog2
 
  • #6
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That's all i have to do right?
 
  • #7
G01
Homework Helper
Gold Member
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What about the charge density on the surface of the sphere? You need to take that into account.
 
  • #8
39
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i think this may work:



Electric field at point g=


(1/4*pi*eo)*∫ p d(tao)

= (1/4*pi*eo)*∫chargedensity(z) *radius(x)^2 * sin(theta) d(x) d(theta) d (phi)

will that work?
 

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