Spherical coordinates

  • Thread starter moneyjane
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  • #1
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After converting a surface over the region that [tex]\rho[/tex]=sin[tex]\phi[/tex]cos[tex]\theta[/tex]/a + sin[tex]\phi[/tex]sin[tex]\theta[/tex]/b + cos[tex]\phi[/tex]/c
I also have that this region is equal to 1.

I cant seem to get anywhere..
 

Answers and Replies

  • #2
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After converting a surface over the region that [tex]\rho[/tex]=sin[tex]\phi[/tex]cos[tex]\theta[/tex]/a + sin[tex]\phi[/tex]sin[tex]\theta[/tex]/b + cos[tex]\phi[/tex]/c
I also have that this region is equal to 1.

I cant seem to get anywhere..
And your question is?
 
  • #3
4
0
haha sorry. i meant to ask how would i get the range for p.
 
  • #4
HallsofIvy
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Well, [itex]\rho[/itex] can't be less than 0. What is the maximum value of [itex]\rho[/itex]?
 
  • #5
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the max is one.
 
  • #6
783
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Moneyjane,

Could you show your work to get to the maximum of 1 ?

Thanks
 

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