- #1

bomba923

- 760

- 0

Just curious, why is [tex] \phi [/tex] calculated as the angle between the +z axis and a position vector of a point of a function, as projected onto the yz plane? Why this convention?

In polar & cylindrical, [tex] \theta [/tex] is calculated from the +x axis to the +y axis (counterclockwise) for position vectors.

*So, why not extrapolate

In polar & cylindrical, [tex] \theta [/tex] is calculated from the +x axis to the +y axis (counterclockwise) for position vectors.

*So, why not extrapolate

**alphabetically**, to have the [tex] \phi [/tex] be the angle between the +**y**axis and the position vector of a point as projected onto the yz plane?
Last edited: